How do solve the following linear system?: -x-7y=14 , x-2y=8 x7y=14,x2y=8?

1 Answer
Apr 2, 2016

(x,y)=(28/9,-22/9)(x,y)=(289,229)

Explanation:

Solve by elimination and substitution

color(blue)(-x-7y=14x7y=14

color(blue)(x-2y=8x2y=8

We can eliminate xx in the first equation by -xx in the second equation

Add both the equations

rarr(-x-7y=14)+(x-2y=8)(x7y=14)+(x2y=8)

rarr-9y=229y=22

color(green)(rArry=-22/9y=229

Substitute the value of yy to the second equation

rarrx-2(-22/9)=8x2(229)=8

rarrx+44/9=8x+449=8

color(green)(rArrx=8-44/9=28/9x=8449=289

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Check (-x-7y=14x7y=14)

rarr-28/9-7(-22/9)=142897(229)=14

rarr-28/9+154/9=14289+1549=14

rarr(-28+154)/9=1428+1549=14

rarr126/9=141269=14

color(orange)(rArr14=1414=14

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Check (x-2y=8x2y=8)

rarr28/9-2(-22/9)=82892(229)=8

rarr28/9+44/9=8289+449=8

rarr(28+44)/9=828+449=8

rarr72/9=8729=8

color(violet)(rArr8=88=8

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:. color(blue)( ul bar |(x,y)=28/9,-22/9|