How do you solve $x = - 3 y - 14$ $x=-3y-14$ and $x = y - 3$ $x=y-3$ using substitution?

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Answer 1 · 2018-03-19T12:41:20

$x = 6.75$ $x = 6.75$
$y = - 2.25$ $y = -2.25$

Apply the substitution method:

$x = - 3 y - 12$ $x = -3y-12$
$x = y - 3$ $x = y -3$

$- 3 y - 12 = y - 3$ $-3y - 12 = y -3$

Simplify

$- 4 y = 9$ $-4y = 9$

$y = - \frac{9}{4} = - 2.25$ $y = -9/4 = -2.25$

So

$x = - 3 y - 12$ $x = -3y - 12$

$x = - 3 (- \frac{9}{4}) - 12$ $x = -3(-9/4) - 12$

$x = 6.75$ $x = 6.75$

How do you solve x=−3y−14x=-3y-14 and x=y−3x=y-3 using substitution?