How do you find the point of intersection for $x-y=3$ and $x-2y=3$ ?

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How do you find the point of intersection for $x-y=3$ and $x-2y=3$ ?

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Answer 1 · 2015-06-27T12:49:53

Ifound:
$x=3$
$y=0$

Explanation:

You can solve the System formed by the two equations trying to find values of $x$ and $y$ that simultaneously satisfy the two equations.
Isolate $x$ from the first equation:
$x=3+y$ substitute for $x$ into the second equation:
$(3+y)-2y=3$
$3+y-2y=3$
So: $y=0$
Substitute back into the first equation:
$x=3+0=3$

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How do you find the point of intersection for $x-y=3$ and $x-2y=3$ ?

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How do you find the point of intersection for x-y=3x-y=3 and x-2y=3x-2y=3?

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How do you find the point of intersection for $x-y=3$ and $x-2y=3$ ?