How do solve the following linear system?: $- 4 x + 4 = - 4 y, 7 x + 6 y + 11 = 0$ $-4x + 4 = -4y, 7x + 6y + 11 = 0$ ?

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How do solve the following linear system?: $- 4 x + 4 = - 4 y, 7 x + 6 y + 11 = 0$ $-4x + 4 = -4y, 7x + 6y + 11 = 0$ ?

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Answer 1 · 2016-07-15T16:20:52

The solution is $(- \frac{5}{13}, \frac{8}{13})$ $(-5/13, 8/13)$

Explanation:

This problem makes things fairly easy for you by providing a clear definition of $y$ $y$ in the first equation:

$- 4 x + 4 = - 4 y$ $-4x + 4 = -4y$
$x - 1 = y$ $x - 1 = y$

We can plug this into the other equation to solve for $x$ $x$ and then use it to find $y$ $y$ :
$7 x + 6 (x - 1) + 11 = 0$ $7x + 6(x - 1) + 11 = 0$
$7 x + 6 x - 6 + 11 = 0$ $7x + 6x - 6 + 11 = 0$
$13 x + 5 = 0$ $13x + 5 = 0$
$x = - \frac{5}{13}$ $x = -5/13$

Then:
$- \frac{5}{13} + 1 = y$ $-5/13 + 1 = y$
$y = \frac{8}{13}$ $y = 8/13$

So the solution is $(- \frac{5}{13}, \frac{8}{13})$ $(-5/13, 8/13)$

A little additional info on the problem in concluding. In case it is not clear, the solution takes the form of a point, $(x, y)$ $(x,y)$ . This is because solving a system of equations is the same as finding the point(s) at which those lines (or curves) intersect.

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How do solve the following linear system?: $- 4 x + 4 = - 4 y, 7 x + 6 y + 11 = 0$ $-4x + 4 = -4y, 7x + 6y + 11 = 0$ ?

1 Answer

Explanation:

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Science

Math

Humanities

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How do solve the following linear system?: -4x + 4 = -4y, 7x + 6y + 11 = 0 −4x+4=−4y,7x+6y+11=0-4x + 4 = -4y, 7x + 6y + 11 = 0 ?

1 Answer

Explanation:

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Impact of this question

How do solve the following linear system?: $- 4 x + 4 = - 4 y, 7 x + 6 y + 11 = 0$ $-4x + 4 = -4y, 7x + 6y + 11 = 0$ ?