Solve the equations 2a−3b=−5, 4a+3b=17 and 5c−2a=1?
2 Answers
Jan 19, 2017
Explanation:
Adding (A) and (B), we get
i.e.
Putting this in (B), we get
or
and putting value of
or
and
Jan 19, 2017
Explanation:
If we add the first 2 equations, we will eliminate b and be able to solve for a
2a−3b=−5×x→(1)
4a+3b=×17×→(2)
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6a+0x=×12⇒a=2 Substitute a = 2 into (2)
(4×2)+3b=17⇒8+3b=17
⇒3b=17−8=9⇒b=3 Substitute a = 2 into the third equation and solve for c
⇒5c−(2×2)=1⇒5c−4=1
⇒5c=1+4=5⇒c=1
Thus a=2,b=3 and c=1