Need help with solving 4x-y=9, x-3y=16?

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Answer 1 · 2018-06-03T04:15:43

$x$ $x$ is equal to $1$ $1$ and $y$ $y$ is equal to $- 5$ $-5$ .

${(4x-y=9), (x-3y=16) :}$

Do

$4x-y=9$
$(x-3y)xx4=16xx4$

So

${(4x-y=9), (4x-12y=64) :}$

Subtract the two equations

$0x+11y= -55$

$11y=-55$

$y=-5$

Replace $y$ in the first equation

$4x-y=9$

$4x-(-5)=9$

$4x+5=9$

$4x=4$

$x=1$