How do you solve the following system: #4x + 7y = 6, 2x + 3y = 34#?

1 Answer
Alan P.
Dec 6, 2015

(x,y)=(110,-64)

Explanation:

Given:
[1]#color(white)("XXX")4x+7y=6#
[2]#color(white)("XXX")2x+3y=34#

Multiply [2] by #2# to give #x# the same coefficient as in [1]
[3]#color(white)("XXX")4x+6y=68#

Subtract [3] from [1] eliminating the #x# term
[4]#color(white)("XXX")y=-62#

Substitute #(-62)# for #y# in [2] and simplify to solve for #x#
[5]#color(white)("XXX")2x+3xx(-62)=34#

[6]#color(white)("XXX")2x-186 = 34#

[7]#color(white)("XXX")2x= 220#

[8]#color(white)("XXX")x=110#

Related questions
See all questions in Systems Using Substitution
Impact of this question
1692 views around the world
You can reuse this answer
Creative Commons License