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How do solve the following linear system?: # x-3y=-1 , 6x-4y=-1 #?

1 Answer

Nov 24, 2015

#x=1/14#, #y=5/14#

Explanation:

Since both expressions equal #-1#, the expressions must equal each other. So, we know that

#x-3y=6x-4y#, and thus #5x=y#.

Substitute this relation for #y# in the first equation, to obtain

#x-3(5x)=-1#, and so #-14x=-1#, and finally #x=1/14#.

Since #y# is five time #x#, then we have #y=5/14#.

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