How do you solve the system $6x + y = 2$ and $2x – 3y = –10$ ?

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Answer 1 · 2018-05-11T11:20:36

$y=3.2$
$x=-1/5$

$6x+y=2$ --- (1)
$2x-3y=-10$ --- (2)

From (1)

$6x+y=2$
$y=2-6x$ --- (3)

Sub (3) into (2)

$2x-3(2-6x)=-10$
$2x-6+18x=-10$
$20x=-4$
$x=-1/5$ --- (4)

Sub (4) into (3)
$y=2-6x$
$y=2-6times-1/5$
$y=3.2$

How do you solve the system 6x + y = 2 6x + y = 2 and 2x – 3y = –10 2x – 3y = –10 ?