How do you solve y=2x+7y=2x+7 and y=5x+4y=5x+4 using substitution? Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer Alexander Jul 9, 2016 2x+7=5x+42x+7=5x+4 Subtract 2x2x from both sides, giving us (2x-2x)+7=(5x-2x)+4(2x−2x)+7=(5x−2x)+4 7=3x+47=3x+4 Subtract 44 from both sides, which finally gives us 3=3x3=3x, so x = 1x=1 Answer link Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve y=-6x-3y=−6x−3 and y=3y=3 using the substitution method? How do you solve 12y-3x=-112y−3x=−1 and x-4y=1x−4y=1 using the substitution method? Which method do you use to solve the system of equations y=1/4x-14y=14x−14 and y=19/8x+7y=198x+7? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve x+y=5x+y=5 and 3x+y=153x+y=15 using the substitution method? What is the point of intersection of the lines x+2y=4x+2y=4 and -x-3y=-7−x−3y=−7? See all questions in Systems Using Substitution Impact of this question 4557 views around the world You can reuse this answer Creative Commons License