How do you solve the system of equations $x+ 2y = 3$ and $- 2x + y = 1$ ?

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How do you solve the system of equations $x+ 2y = 3$ and $- 2x + y = 1$ ?

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Answer 1 · 2017-07-30T22:04:38

Pick either one of the equations and make either $x$ or $y$ the subjects of the formula and substitute the value of either $y$ or $x$ into the other equation.

Explanation:

I.e. $" "x=3-2y" "$ (from first equation)

Now substitute $x$ above into second equation:

$-2(3-2y)+y=1$

$-6+4y+y=1$

$-6+5y=1$

$5y=7$

Therefore

$y=7/5$

Now substitute the $y$ -value into the equation to find $x$ :

$-2x+7/5=1$

$-2x=5/5(=1) -7/5$

$x=1/5$

Thus, $x$ and $y$ for the 2nd equation $=1/5$ and $=7/5$ .

You must again substitute either into the 1st equation to find those values. Just remember to check the answers!

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How do you solve the system of equations $x+ 2y = 3$ and $- 2x + y = 1$ ?

1 Answer

Explanation:

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Science

Math

Humanities

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How do you solve the system of equations x+ 2y = 3x+ 2y = 3 and - 2x + y = 1- 2x + y = 1?

1 Answer

Explanation:

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How do you solve the system of equations $x+ 2y = 3$ and $- 2x + y = 1$ ?