How do you solve 2x-y=4 and 7x+3y=27 using substitution?

1 Answer
Sep 1, 2017

See a solution process below:

Explanation:

Step 1) Solve the first equation for y:

2x - y = 4

-color(red)(2x) + 2x - y = -color(red)(2x) + 4

0 - y = -2x + 4

-y = -2x + 4

color(red)(-1) xxx -y = color(red)(-1)(-2x + 4)

y = (color(red)(-1) xx -2x) + (color(red)(-1) xx 4)

y = 2x - 4

Step 2) Substitute (2x - 4) for y in the second equation and solve for x:

7x + 3y = 27 becomes:

7x + 3(2x - 4) = 27

7x + (3 xx 2x) - (3 xx 4) = 27

7x + 6x - 12 = 27

(7 + 6)x - 12 = 27

13x - 12 = 27

13x - 12 + color(red)(12) = 27 + color(red)(12)

13x - 0 = 39

13x = 39

(13x)/color(red)(13) = 39/color(red)(13)

(color(red)(cancel(color(black)(13)))x)/cancel(color(red)(13)) = 3

x = 3

Step 3) Substitute 3 for x in the solution to the first equation at the end of Step 1 and calculate y:

y = 2x - 4 becomes:

y = (2 xx 3) - 4

y = 6 - 4

y = 2

The Solution Is: x = 3 and y = 2 or (3, 2)