How do you solve the system of equations $2 x + 3 y = 105$ $2x+3y=105$ and $x + 2 y = 65$ $x+2y=65$ ?

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How do you solve the system of equations $2 x + 3 y = 105$ $2x+3y=105$ and $x + 2 y = 65$ $x+2y=65$ ?

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Answer 1 · 2018-04-19T02:35:01

$x$ $x$ equals $15$ $15$ and $y$ $y$ equals $25$ $25$ .

Explanation:

Set the easiest equation to $x$ $x$ (the last one) and because

$x = - 2 y + 65$ $x = -2y+65$

the $x$ $x$ in the other equation also equals that, you can replace the $x$ $x$ in the first equation with the $- 2 y + 65$ $-2y+65$ . Then simplify and solve for the $y$ $y$ .

You can plug the $25$ $25$ into either equation to simplify and solve for $x$ $x$ .

Looks like:

$x = - 2 y + 65$ $x=-2y+65$

so

$2 (- 2 y + 65) + 3 y = 105$ $2(-2y+65)+3y=105$

$- 4 y + 3 y = 105 - 130$ $-4y+3y=105-130$

$y = 25$ $y=25$

And

$x + 2 (25) = 65$ $x+2(25)=65$

$x = 15$ $x=15$

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How do you solve the system of equations $2 x + 3 y = 105$ $2x+3y=105$ and $x + 2 y = 65$ $x+2y=65$ ?

1 Answer

Explanation:

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How do you solve the system of equations $2 x + 3 y = 105$ $2x+3y=105$ and $x + 2 y = 65$ $x+2y=65$ ?