How do you solve # x+3y=8# and #y=2x-9# using substitution?

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How do you solve # x+3y=8# and #y=2x-9# using substitution?

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Answer 1 · 2016-03-06T01:16:04

I found:
#x=5#
#y=1#

Explanation:

You can use the second equation substituting it, for #y#, into the second:
#x+3(color(red)(2x-9))=8#
#x+6x-27=8#
#7x=35#
#x=35/7=5#
We substitute this value of #x# into the second equation to get:
#y=(2*5)-9=10-9=1#

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How do you solve # x+3y=8# and #y=2x-9# using substitution?

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