How do solve the following linear system?: $5 x + 2 y = 2, x + y = 2$ $5x+2y=2, x + y = 2$ ?

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How do solve the following linear system?: $5 x + 2 y = 2, x + y = 2$ $5x+2y=2, x + y = 2$ ?

1 Answer

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Answer 1 · 2016-01-12T22:34:49

$x = - \frac{2}{3}$ $x=-2/3$ and $y = \frac{8}{3}$ $y =8/3$

Explanation:

Subtract y from both sides of the second equation and get $x = 2 - y$ $x=2-y$ . Substitute this value of x in the first equation and get $5 (2 - y) + 2 y = 2$ $5(2-y)+2y=2$ . Expanding the first term gives 10-5y+2y=2.Subtracting 10 from both sides and simplifying gives $- 3 y = - 8$ $-3y=-8$ . So, $y = \frac{8}{3}$ $y=8/3$ . Substituting this value of y in $x = 2 - y$ $x=2-y$ gives $x = 2 - (\frac{8}{3})$ $x=2-(8/3)$ , so $x = \frac{6}{3} - \frac{8}{3}$ $x=6/3 - 8/3$ = $- \frac{2}{3}$ $-2/3$ .

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How do solve the following linear system?: $5 x + 2 y = 2, x + y = 2$ $5x+2y=2, x + y = 2$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do solve the following linear system?: 5x+2y=2, x + y = 2 5x+2y=2,x+y=2 5x+2y=2, x + y = 2 ?

1 Answer

Explanation:

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How do solve the following linear system?: $5 x + 2 y = 2, x + y = 2$ $5x+2y=2, x + y = 2$ ?