How do solve the following linear system?: $5x+2y=1 , 2/3x + 4y = -1$ ?

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Answer 1 · 2016-01-27T08:33:24

$x = 9/28$

$y =17/45$

Rearrange one of the equations to get a variable on its own on the left hand side, then substitute it into the other equation and solve.

$5x+2y =1$
$2/3x +4y = -1$
$2y = 1-5x$
$y = 1/2 - 5/2x$

Substituting into he second equation
$2/3x +4(1/2-5/2x) =-1$
$2/3x +2 -10x = -1$
$2x-30x = -9$
$x=(-9)/(-28) = 9/28$

Then $y=1/2-5/2*(9/28)$
$y = (28-45)/56=17/45$

How do solve the following linear system?: 5x+2y=1 , 2/3x + 4y = -1 5x+2y=1 , 2/3x + 4y = -1 ?