How do you solve the system $y = 3 x + 8$ $y=3x+8$ and $5 x + 2 y = 5$ $5x+2y=5$ using substitution?

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How do you solve the system $y = 3 x + 8$ $y=3x+8$ and $5 x + 2 y = 5$ $5x+2y=5$ using substitution?

1 Answer

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Answer 1 · 2017-06-17T06:32:22

$y = 5$ $y=5$
$x = - 1$ $x=-1$

Explanation:

Given -

$y = 3 x + 8$ $y=3x+8$ -------------- (1)
$5 x + 2 y = 5$ $5x+2y=5$ ------------(2)

Substitute $y = 3 x + 8$ $y=3x+8$ in equation (2)

$5 x + 2 (3 x + 8) = 5$ $5x+2(3x+8)=5$
$5 x + 6 x + 16 = 5$ $5x+6x+16=5$
$11 x = 5 - 16 = - 11$ $11x=5-16=-11$
$x = \frac{- 11}{11} = - 1$ $x=(-11)/11=-1$
$x = - 1$ $x=-1$

Substitute $x = - 1$ $x=-1$ in equation (1)

$y = 3 (- 1) + 8 = - 3 + 8 = 5$ $y=3(-1) +8=-3+8=5$
$y = 5$ $y=5$

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How do you solve the system $y = 3 x + 8$ $y=3x+8$ and $5 x + 2 y = 5$ $5x+2y=5$ using substitution?

1 Answer

Explanation:

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How do you solve the system $y = 3 x + 8$ $y=3x+8$ and $5 x + 2 y = 5$ $5x+2y=5$ using substitution?