How do you solve the following linear system: $x - 3y = -3, x + 3y = 9,$ ?

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Answer 1 · 2016-04-01T14:58:42

$x=3$
$y=2$

The given equations are
$x-3y=-3" "$ first equation
$underline(x+3y=9" ")$ second equation
$2x+0=6$ $larr$ the result after adding the terms

and $2x=6$

$x=3$

We can now solve for $y$ using $x=3$ and second equation

$x+3y=9" "$ second equation
$3+3y=9" "$ second equation
$3y=9-3$
$3y=6$

$y=2$

God bless....I hope the explanation is useful.

How do you solve the following linear system: x - 3y = -3, x + 3y = 9, x - 3y = -3, x + 3y = 9, ?