How do you solve the following system: $- 6 x - 2 y = - 14, 4 x - 5 y = - 1$ $-6x-2y=-14, 4x-5y= -1$ ?

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How do you solve the following system: $- 6 x - 2 y = - 14, 4 x - 5 y = - 1$ $-6x-2y=-14, 4x-5y= -1$ ?

1 Answer

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Answer 1 · 2017-09-29T15:10:37

$x = (\frac{34}{19})$ $x=(34/19)$ & $y = (\frac{31}{19})$ $y=(31/19)$

Explanation:

$6 x + 2 y = 14$ $6x+2y=14$
$3 x + y = 7$ $3x+y=7$ (Equation 1)
$4 x - 5 y = - 1$ $4x-5y=-1$ (Equation 2)
Multiply Equation 1 by 5
$15 x + 5 y = 35$ $15x+5y=35$ (Equation 3)
Add Equation 2. & Equation 3
$19 x = 35 - 1 = 34$ $19x=35-1=34$
$x = (\frac{34}{19})$ $x=(34/19)$
Substituting value of x in Equation 1,
$3 . (\frac{34}{19}) + y = 7$ $3.(34/19)+y=7$
$y = 7 - 3 (\frac{34}{19})$ $y=7-3(34/19)$
$y = (133 - 102) 19 = \frac{31}{19}$ $y=(133-102)19=31/19$

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How do you solve the following system: $- 6 x - 2 y = - 14, 4 x - 5 y = - 1$ $-6x-2y=-14, 4x-5y= -1$ ?

1 Answer

Explanation:

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Science

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Humanities

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How do you solve the following system: −6x−2y=−14,4x−5y=−1-6x-2y=-14, 4x-5y= -1 ?

1 Answer

Explanation:

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How do you solve the following system: $- 6 x - 2 y = - 14, 4 x - 5 y = - 1$ $-6x-2y=-14, 4x-5y= -1$ ?