How do you solve the following system: $-6x-2y=-14, 4x-5y= -1$ ?

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How do you solve the following system: $-6x-2y=-14, 4x-5y= -1$ ?

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Answer 1 · 2017-09-29T15:10:37

$x=(34/19)$ & $y=(31/19)$

Explanation:

$6x+2y=14$
$3x+y=7$ (Equation 1)
$4x-5y=-1$ (Equation 2)
Multiply Equation 1 by 5
$15x+5y=35$ (Equation 3)
Add Equation 2. & Equation 3
$19x=35-1=34$
$x=(34/19)$
Substituting value of x in Equation 1,
$3.(34/19)+y=7$
$y=7-3(34/19)$
$y=(133-102)19=31/19$

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How do you solve the following system: $-6x-2y=-14, 4x-5y= -1$ ?

1 Answer

Explanation:

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How do you solve the following system: -6x-2y=-14, 4x-5y= -1 -6x-2y=-14, 4x-5y= -1 ?

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How do you solve the following system: $-6x-2y=-14, 4x-5y= -1$ ?