How do you solve by substitution #x= y - 11# and #x - 3y = 1#?
1 Answer
May 19, 2015
x = y - 11 . Substitute x by (y - 11) into equation 2.
x - 3y = 1 -> (y - 11) - 3y = 1 -> -2y = 12 ->
Check:
