Distance Formula
Key Questions
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Answer:
Let's see.
Explanation:

I have drawn a graph in which there are two points
color(red)(p_1(x_1,y_1))" and "color(red)(p_2(x_2,y_2) .- We can easily say that
" "bar(OD)=x_1" ; "bar(OE)=x_2" ; "bar(AD)=y_1" ; "bar(EB)=y_2
We also have a rectangle
square OCED . So,color(red)(bar(AC)=bar(DE)) " and "color(red)(bar(AD)=bar(CE) Now,
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bar(AC)=bar(DE)=bar(OE)-bar(OD)=(x_2 -x_1) -
bar(BC)=bar(BE)-bar(CE)=bar(BE)-bar(AD)=(y_2-y_1)
With the help of Pythagorean theorem,
bar(AB)^2=bar(BC)^2+bar(AC)^2 bar(AB)^2=(x_2-x_1)^2+(y_2-y_1)^2 bar(AB)=sqrt((x_2-x_1)^2+(y_2-y_1)^2 N.B:- As it is a square value , you may take
(x_1-x_2) or,(x_2-x_1) . I mean you have to take difference.That's(x_1~x_2) So, the required formula is proved that
If the distance between two points
color(green)(p_1(x_1,y_1) andcolor(green)(p_2(x_2,y_2) iscolor(red)(r ,then,
color(red)(ul(bar(|color(green)(r=sqrt((x_1-x_2)^2+(y_1-y_2)^2))| Hope it helps...
Thank you... - We can easily say that
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Distance Formula
The distance
D between two points(x_1,y_1) and(x_2,y_2) can be found byD=sqrt{(x_2-x_1)^2+(y_2-y_1)^2}
Example
Find the distance between the points
(1,-2) and(5,1) .Let
(x_1,y_1)=(1,-2) and(x_2,y_2)=(5,1) .By Distance Formula above,
D=sqrt{(5-1)^2+[1-(-2)]^2}=sqrt{16+9}=sqrt{25}=5
I hope that this was helpful.
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Given the two points
(x_1, y_1) and(x_2, y_2) the distance between these points is given by the formula:d=sqrt((x_2-x_1)^2+(y_2-y_1)^2 ) All you have to do is plug in the given points given to the distance formula and solve.
Questions
Radicals and Geometry Connections
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Graphs of Square Root Functions
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Simplification of Radical Expressions
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Addition and Subtraction of Radicals
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Multiplication and Division of Radicals
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Radical Equations
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Pythagorean Theorem and its Converse
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Distance Formula
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Midpoint Formula
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Measures of Central Tendency and Dispersion
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Stem-and-Leaf Plots
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Box-and-Whisker Plots