What is the distance between #(–6, 3, 1) # and #(4, 4, 2) #?

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Answer 1 · 2017-02-16T07:16:41

The distance between #(-6,3,1)# and #(4,4,2)# is #12.083#

Just like #(x,y)# represents a point on a plane i.e. in #2#-dimension,

#(x,y,z)# represents a point in #3#-dimension.

and distance between two points #(x_1,y_1,z_1)# and #(x_2,y_2,z_2)# is

#sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)#

Therefore, distance between #(-6,3,1)# and #(4,4,2)# is

#sqrt((6-(-6))^2+(4-3)^2+(2-1)^2)#

= #sqrt((6+6)^2+(4-3)^2+(2-1)^2)#

= #sqrt(12^2+1^2+1^2)=sqrt(144+1+1)=sqrt146=12.083#