What is the distance between $(3, 4, 1)$ $(3, 4, 1)$ and $(3, 6, 2)$ $(3, 6, 2)$ ?

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What is the distance between $(3, 4, 1)$ $(3, 4, 1)$ and $(3, 6, 2)$ $(3, 6, 2)$ ?

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Answer 1 · 2015-12-06T13:35:13

$\sqrt{5}$ $sqrt5$

Explanation:

Distance between 2 points $(x 1, y 1, z 1) and (x 2, y 2, z 2)$ $(x1,y1,z1) and (x2,y2,z2)$ = $\sqrt{{(x 2 - x 1)}^{2} + {(y 2 - y 1)}^{2} + {(z 2 - z 1)}^{2}}$ $sqrt((x2-x1)^2+(y2-y1)^2+(z2-z1)^2)$

So distance between (3,4,1) and (3,6,2) = $\sqrt{{(3 - 3)}^{2} + {(6 - 4)}^{2} + {(2 - 1)}^{2}}$ $sqrt((3-3)^2+(6-4)^2+(2-1)^2)$

= $\sqrt{5}$ $sqrt5$

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What is the distance between $(3, 4, 1)$ $(3, 4, 1)$ and $(3, 6, 2)$ $(3, 6, 2)$ ?

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What is the distance between (3, 4, 1) (3,4,1)(3, 4, 1) and (3, 6, 2) (3,6,2)(3, 6, 2) ?

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What is the distance between $(3, 4, 1)$ $(3, 4, 1)$ and $(3, 6, 2)$ $(3, 6, 2)$ ?