What is the distance between P(–2, 1, 3) and point Q(–1, 4, –2)?

1 Answer
Narad T.
Nov 7, 2016

The distance PQ=sqrt35PQ=√35

Explanation:

We can do it using vectors.
vec(PQ)=〈-1,4,-2〉-〈-2,1,3〉=〈1,3,-5〉−−→PQ=⟨−1,4,−2⟩−⟨−2,1,3⟩=⟨1,3,−5⟩
The distance PQPQ is equal to the modulus of vec(PQ)−−→PQ
= || vec(PQ) || =sqrt(1+9+25)=sqrt35=∣∣∣∣∣∣−−→PQ∣∣∣∣∣∣=√1+9+25=√35

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