What is the distance between $(5, –1)$ and $(-4, 6)$ ?

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Answer 1 · 2018-06-06T02:31:16

$d = sqrt(130)$

Distance:

$d = sqrt((y_2-y_1)^2+(x_2-x_1)^2)$

We have:

$(x_1,y_1) = (5,-1)$

and

$(x_2,y_2) = (-4,6)$

This gives us a distance of

$d = sqrt((6-(-1))^2+(-4-5)^2)$

$d = sqrt((7)^2+(-9)^2)$

$d = sqrt(49+81)$

$d = sqrt(130)$

What is the distance between (5, –1)(5, –1) and (-4, 6) (-4, 6) ?