What is the distance of (1,-3) and (4,3)?

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What is the distance of (1,-3) and (4,3)?

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Answer 1 · 2018-04-19T19:14:30

$3sqrt5$

Explanation:

Distance between two point equation is:

$sqrt((x_2-x_1)^2+(y_2-y_1)^2$

Take $(1,-3)$ as $(x_1, y_1)$
Take $(4,3)$ as $(x_2, y_2)$

Substitute into equation:

$sqrt((4-1)^2+(3--3)^2$

Simplify to get $3sqrt5$

Answer 2 · 2018-04-19T19:14:39

$sqrt45~~6.708" to 3 dec. places"$

Explanation:

$"using the "color(blue)"distance formula"$

$•color(white)(x)d=sqrt((x_2-x_1)^2+(y_2-y_1)^2)$

$"let "(x_1,y_1)=(1,-3)" and "(x_2,y_2)=(4,3)$

$d=sqrt((4-1)^2+(3-(-3))^2)$

$color(white)(d)=sqrt(9+36)=sqrt45~~6.708$

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What is the distance of (1,-3) and (4,3)?

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