# What is the distance between (–4, 7)  and  (–5, 13) ?

$\sqrt{37}$
$I f , A \left({x}_{1} , {y}_{1}\right) \mathmr{and} B \left({x}_{2} , {y}_{2}\right) , t h e n , d \left(A , B\right) = \textcolor{red}{A B = \sqrt{{\left({x}_{1} - {x}_{2}\right)}^{2} + {\left({y}_{1} - {y}_{2}\right)}^{2}}}$
$A B = \sqrt{{\left(- 4 + 5\right)}^{2} + {\left(7 - 13\right)}^{2}} = \sqrt{1 + 36} = \sqrt{37}$