What is the distance between (5,-3)(5,3) and (3,7) (3,7)?

1 Answer
Jul 25, 2018

The distance is 2sqrt26226 or about 10.19810.198 (rounded to nearest thousandth's place).

Explanation:

The formula for the distance of 2-dimensional coordinates is: d = sqrt((x_2-x_1)^2 + (y_2-y_1)^2)d=(x2x1)2+(y2y1)2

We have the two coordinates, so we can plug in the values for xx and yy:
d = sqrt((3 - 5)^2 + (7 - (-3))^2)d=(35)2+(7(3))2

Now we simplify:
d = sqrt((-2)^2 + (10)^2)d=(2)2+(10)2

d = sqrt(4 + 100)d=4+100

d = sqrt(104)d=104

d = 2sqrt26d=226

If you want to leave it in exact form, you can leave the distance as 2sqrt26226. However, if you want the decimal answer, here it is rounded to the nearest thousandth's place:
d ~~ 10.198d10.198

Hope this helps!