What is the distance between #(8, 2) # and # (4, 7) #?

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What is the distance between #(8, 2) # and # (4, 7) #?

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Answer 1 · 2015-12-29T06:02:53

Its #sqrt(41)#

Explanation:

We first need to calculate the difference in x axis and in y axis:
#trianglex = 8 - 4 = 4#
#triangley = 7 - 2 = 5#
Having this values, we now have a triangle rectangle with angles in both points. Now, just apply Pythagoras' formula:
#"line"^2 = trianglex^2 + triangley^2#
#"line"^2 = 4^2 + 5^2#
#"line" = sqrt(41)#

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What is the distance between #(8, 2) # and # (4, 7) #?

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