How do you find the distance between (10,19), (-13,9)?

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Answer 1 · 2017-08-17T12:08:01

Use $a^2 + b^2 = c^2$

$c = 25.1$

Let the change in x be $a^2$
Let the change in y be $b^2$

The the square root of $c^2$ = the distance

$a^2 = (19-9)^2$

$a^2 = 100$

$b^2 = ( 10- -13)^2$

$b^2 = 529$

$100 + 529 = 629$

$629 = c^2$

square root of $629 = c$

$c= sqrt629$

$c= 25.1$

Answer 2 · 2017-08-17T13:10:44

$=25.08$

The formula for the distance between two points is based on the Theorem of Pythagoras.

$|AB| = sqrt((x_2-x_1)^2 + (y_2-y_1)^2))$

We have the points $(10,19) and (-13,9)$

Distance = $sqrt((10-(-13))^2 +(19-9)^2)$

$= sqrt(23^2 +10^2)$

$=sqrt629$

$=25.08$