How do you find the perimeter of a triangle whose coordinates are (10,2) and (7,-3)?

1 Answer
Jun 4, 2015

Assuming the third coordinate is the origin #(0,0)#

Using the Pythagorean Theorem:

#color(white)("XXXX")#Distance #(0,0)# to #(10,2)#
#color(white)("XXXX")##color(white)("XXXX")##sqrt(10^2+2^2) = sqrt(104)#

#color(white)("XXXX")#Distance #(0,0)# to #(7,-3)#
#color(white)("XXXX")##color(white)("XXXX")##sqrt(7^2+(-3)^2) = sqrt(58)#

#color(white)("XXXX")#Distance #(10,2)# to #(7,-3)#
#color(white)("XXXX")##color(white)("XXXX")##sqrt(3^2+5^2) =sqrt(34)#

Perimeter = #sqrt(104) + sqrt(58)+sqrt(34)#

(perhaps this would have been a prettier answer with a third point other than the origin)