How do you find the perimeter of a triangle whose coordinates are (10,2) and (7,-3)?

1 Answer
Jun 4, 2015

Assuming the third coordinate is the origin (0,0)

Using the Pythagorean Theorem:

color(white)("XXXX")Distance (0,0) to (10,2)
color(white)("XXXX")color(white)("XXXX")sqrt(10^2+2^2) = sqrt(104)

color(white)("XXXX")Distance (0,0) to (7,-3)
color(white)("XXXX")color(white)("XXXX")sqrt(7^2+(-3)^2) = sqrt(58)

color(white)("XXXX")Distance (10,2) to (7,-3)
color(white)("XXXX")color(white)("XXXX")sqrt(3^2+5^2) =sqrt(34)

Perimeter = sqrt(104) + sqrt(58)+sqrt(34)

(perhaps this would have been a prettier answer with a third point other than the origin)