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Answer 1 · 2017-06-10T13:26:20

$2sqrt(10)" "$ as an exact value

When 'reading' a graph in '2-space' (x and y axis) then you always read left to right on the x-axis

Let point 1 be $P_1->(x_1,y_1)=(-1,-3)$
Let point 2 be $P_2->(x_2,y_2)=(1,3)$
Let the direct distance from $P_1" to "P_2$ be $d$

The link between Pythagoras and the distance between two points is due to the triangle depicted in the graph below:

Tony B Tony B

Thus we have: $d^2=(x_2-x_1)^2+(y_2-y_1)^2$

$=> d=sqrt((x_2-x_1)^2+(y_2-y_1)^2)$

$=> d=sqrt([1-(-1)]^2+[3-(-3)]^2)$

$d=sqrt(4+36)" "=sqrt(40)$

$d=sqrt(2^2xx10)" "=2sqrt(10)" "$ as an exact value