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What is the distance between #(-2,1,-13)# and #(4,3,-12)#?

1 Answer

May 3, 2016

#s=sqrt41#

Explanation:

#A=(-2,1,-13)#
#B=(4,3,-12)#

#A_x=-2#
#A_y=1#
#A_z=-13#

#B_x=4#
#B_y=3#
#B_z=-12#

#"distance between A and B can be calculated by formula:"#
#s=sqrt((B_x-A_x)^2+(B_y-A_y)^2+(B_z-A_z)^2)#

#s=sqrt((4+2)^2+(3-1)^2+(-12+13)^2)#

#s=sqrt(6^2+2^2+1^2)=sqrt(36+4+1)=sqrt(41)#

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