How do you find the value of a given the points (-4,1), (a,8) with a distance of sqrt50?

1 Answer
Mar 24, 2018

See a solution process below:

Explanation:

The formula for calculating the distance between two points is:

d = sqrt((color(red)(x_2) - color(blue)(x_1))^2 + (color(red)(y_2) - color(blue)(y_1))^2)

Substituting the information from the problem and solving for a gives:

sqrt(50) = sqrt((color(red)(a) - color(blue)(-4))^2 + (color(red)(8) - color(blue)(1))^2)

sqrt(50) = sqrt((color(red)(a) + color(blue)(4))^2 + (color(red)(8) - color(blue)(1))^2)

sqrt(50) = sqrt((color(red)(a) + color(blue)(4))^2 + 7^2)

sqrt(50) = sqrt(a^2 + 8a + 16 + 49)

sqrt(50) = sqrt(a^2 + 8a + 65)

(sqrt(50))^2 = (sqrt(a^2 + 8a + 65))^2

50 = a^2 + 8a + 65

50 - color(red)(50) = a^2 + 8a + 65 - color(red)(50)

0 = a^2 + 8a + 15

0 = (a + 3)(a + 5)

Solution 1:

a + 3 = 0

a + 3 - color(red)(3) = 0 - color(red)(3)

a + 0 = -3

a = -3

Solution 2:

a + 5 = 0

a + 5 - color(red)(5) = 0 - color(red)(5)

a + 0 = -5

a = -5

The Solution Is:

color(red)(a) can be either -3 or -5 for the two points to have a distance of sqrt(50)