How do you find the distance between (7,3), (-1,-4)?

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Answer 1 · 2016-08-22T18:11:11

$=10.63$

$=sqrt((-1-7)^2+(-4-3)^2)$

$=sqrt((-8)^2+(-7)^2)$

$=sqrt(64+49)$

$=sqrt(113)$

$=10.63$

Answer 2 · 2016-08-22T18:12:18

The distance between $(7,3)$ and $(-1,-4)$ is $10.63$ .

The distance between two points $(x _1,y_1)$ and $(x _2,y_2)$ is given by

$sqrt((x_2-x_1)^2+(y_2-y_1)^2)$ .

Hence distance between $(7,3)$ and $(-1,-4)$ is

$sqrt((-1-7)^2+(-4-3)^2)$

= $sqrt((-8)^2+(-7)^2)$

= $sqrt(64+49)$

= $sqrt113=10.63$