What is the distance between $(4, 3, 1)$ $(4, 3, 1)$ and $(3, 6, 2)$ $(3, 6, 2)$ ?

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What is the distance between $(4, 3, 1)$ $(4, 3, 1)$ and $(3, 6, 2)$ $(3, 6, 2)$ ?

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Answer 1 · 2016-02-02T11:07:37

Distance = $\sqrt{11} u n i t s$ $sqrt 11 units$

Explanation:

The Distance Formula is $D = \sqrt{{(x_{2} - x_{1})}_{2}^{2} + {(y_{2} - y_{1})}_{2}^{2} + {(z_{2} - z_{1})}_{2}^{2}}$ $D=sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)$ or $D = \sqrt{{(3 - 4)}^{2} + {(6 - 3)}^{2} + {(2 - 1)}^{2}} = \sqrt{1 + 9 + 1} = \sqrt{11}$ $D=sqrt((3-4)^2+(6-3)^2+(2-1)^2) = sqrt(1+9+1) =sqrt 11$ [Ans]

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What is the distance between $(4, 3, 1)$ $(4, 3, 1)$ and $(3, 6, 2)$ $(3, 6, 2)$ ?

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What is the distance between $(4, 3, 1)$ $(4, 3, 1)$ and $(3, 6, 2)$ $(3, 6, 2)$ ?