What is the distance between $(–3, –2)$ and $(5, 2)$ ?

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Answer 1 · 2016-04-02T04:08:01

$4sqrt5$

The distance, $r$ , between two points with coordinates $(x_1,y_1)$ and $(x_2,y_2)$ is given by

$r = sqrt((x_1 - x_2)^2 + (y_1 - y_2)^2)$

mathsfirst.massey.ac.nz

It is an application of Pythagoras Theorem.

Therefore, the distance between $(-3,-2)$ and $(5,2)$ is

$sqrt((-3 - 5)^2 + (-2 - 2)^2) = sqrt(64+16)$

$= sqrt80$

$= 4sqrt5$

Answer 2 · 2016-04-02T08:24:38

$4sqrt5$

$color(blue)((-3,-2)and(5,2)$

enter image source here

So,

$color(purple)(x_1=-3,x_2=5$

$color(purple)(y_1=-2,y_2=2$

$:.d=sqrt((-3-5)^2+(-2-2)^2)$

$rarrsqrt((-8)^2+(-4)^2)$

$rarrsqrt(64+16)$

$rarrsqrt80$

$rarrsqrt(16*5)$

$color(green)(rArr4sqrt5$

What is the distance between (–3, –2)(–3, –2) and (5, 2)(5, 2)?