What is the distance between (3, –1, 1) and (1, –2, 0) ?
1 Answer
Apr 18, 2017
Explanation:
Use the 3-d version of the
color(blue)"distance formula"
color(red)(bar(ul(|color(white)(2/2)color(black)(d=sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2))color(white)(2/2)|)))
where(x_1,y_1,z_1),(x_2,y_2,z_2)" are 2 coordinate points"
"the 2 points here are " (3,-1,1)" and " (1,-2,0)
"let " (x_1,y_1,z_1)=(3,-1,1),(x_2,y_2,z_2)=(1,-2,0)
d=sqrt((1-3)^2+(-2+1)^2+(0-1)^2)
color(white)(d)=sqrt(4+1+1)
color(white)(d)=sqrt6~~2.45" to 2 dec. places"
