What is the distance between $(3,6,-2)$ and $(-3,-3,-1)$ ?

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Answer 1 · 2015-12-01T11:43:45

distance $= 6sqrt(3)$

Given $(x,y,z)$ coordinate points $(3,6,-2)$ and $(-3,-3,-1)$

$(deltax,deltay,deltaz) = (6,9,1)$

and the distance between the points
$= sqrt(6^2+9^2+1^1) = sqrt(36+81+1) = sqrt(118) = 6sqrt(3)$

What is the distance between (3,6,-2)(3,6,-2) and (-3,-3,-1)(-3,-3,-1)?