What is the distance between $(2,-14)$ and $(-1,21)$ ?

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Answer 1 · 2016-01-19T22:24:27

Distance between $=sqrt(1234)~~35.128$ to 3 decimal places

This is treated like a triangle where the line between the points is the hypotenuse.

Tony B

The distance we are after is that of AC

Given :
$(x_1,y_1)-> (2,-14)$
$(x_2,y_2)->(-1,21)$

So by Pythagoras

$( AC)^2 = (x_2-x_1)^2+(y_2-y_1)^2$

$(AC)^2=(color(white)(.)(-1) -2)^2 + (21-(-14)color(white)(.))^2$

$(AC)^2=(-3)^2+(35)^2$

$AC=sqrt(1234)~~35.128$ to 3 decimal places

What is the distance between (2,-14)(2,-14) and (-1,21)(-1,21)?