What is the distance between the points (0,0) and (5,12)?

Question

16984 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-29T10:45:16

Hypotenuse, which is 13 units.

If your starting point is origin and your dinal x is 5 and your final y is 12, you can compute the distance by

$m=sqrt(x^2+y^2)$

Your m will be

$m=sqrt(5^2+12+2)$

$m=sqrt(169)$

$m=13$

This is the distance. 13 units.

Answer 2 · 2017-05-29T11:05:24

This is why the solution provided by G_Ozdilec works

The distance between the two points is 13 units

Basically you use the Pythagoras solution for a right tringle.

Tony B

$"Hypotenuse"=sqrt("adjacent"^2+"opposit"^2)$

$"Hypotenuse"=sqrt((x_2-x_1)^2+(y_2-y_1)^2)$

$"Hypotenuse"=sqrt((5-0)^2+(12-0)^2)$

$"Hypotenuse"=sqrt(25+144)$

$"Hypotenuse"=13$

It is good practice to state the units of measurement. However none are given. So if you wish to declare something just use the word 'units'