What is the distance between $(2,15,7)$ and $(2,4,-4)$ ?

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Answer 1 · 2016-06-05T06:27:37

The distance between $(2,15,7)$ and $(2,4,-4)$ is $15.5562$

In a two dimensional plane, distance between two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by

$sqrt((x_2-x_1)^2+(y_2-y_1)^2)$

and in three dimensional space, distance between two points $(x_1,y_1,z_1)$ and $(x_2,y_2,z_2)$ is given by

$sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)$

Hence, the distance between $(2,15,7)$ and $(2,4,-4)$ is

$sqrt((2-2)^2+(4-15)^2+(-4-7)^2)$

= $sqrt(0^2+(-11)^2+(-11)^2)=sqrt(0+121+121)=11sqrt2=15.5562$

What is the distance between (2,15,7)(2,15,7) and (2,4,-4)(2,4,-4)?