What is the distance between $(3, 9)$ $(3, 9)$ and $(9, 1)$ $(9,1)$ ?

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Answer 1 · 2018-04-14T05:21:18

10 units

$\sqrt{{(x_{1} - x_{2})}_{1}^{2} + {(y_{1} - y_{2})}_{1}^{2}}$ $sqrt((x_1-x_2)^2+(y_1-y_2)^2)$

$\sqrt{{(3 - 9)}^{2} + {(9 - 1)}^{2}}$ $sqrt((3-9)^2+(9-1)^2)$

$\sqrt{{(- 6)}^{2} + {(8)}^{2}}$ $sqrt((-6)^2+(8)^2)$

$\sqrt{36 + 64}$ $sqrt(36+64)$

$\sqrt{100} = \pm 10$ $sqrt(100)=pm10$

Since distance is a positive figure, our distance is 10 units.

What is the distance between (3, 9) (3,9)(3, 9) and (9,1)(9,1)(9,1)?