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What is the distance between #(1, -3) # and #(-2, 4) #?

1 Answer

Jan 27, 2016

#sqrt(58)#

Explanation:

#(1,-3)# and #(-2,4)#

So the distance formula is:

#d=sqrt((y2-y1)^2+(x2-x1)^2)#

Plug in the #x# and #y# values.
It should look like this:

#d=sqrt((4+3)^2+(-2-1)^2)#

Solve.
First, work in the parenthesis.
#sqrt((7)^2+(-3)^2)#
Then, do the rest.
#sqrt(49+9)#
#sqrt(58)#
:D

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