What is the distance between (5,-2,4) and (8,8,-1)?

1 Answer
Shantelle
Apr 29, 2018

d = sqrt(134) or ~~ 11.58

Explanation:

The formula for the distance for 3-dimensional coordinates is similar or 2-dimensional; it is: d = sqrt((x_2-x_1)^2 + (y_2-y_1)^2 + (z_2-z_1)^2)

We have the two coordinates, so we can plug in the values for x, y, and z:
d = sqrt((-1-4)^2 + (8-(-2))^2 + (8-5)^2)

Now we simplify:
d = sqrt((-5)^2 + (10)^2 + (3)^2)

d = sqrt(25 + 100 + 9)

d = sqrt(134)

If you want to leave it in exact form, you can leave the distance as sqrt134. However, if you want the decimal answer, here it is rounded to the nearest hundredth's place:
d ~~ 11.58

Hope this helps!

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