How do you solve $y + \frac{1}{2} = 1 - \frac{y}{3}$ $y+1/2 = 1-y/3$ ?

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Answer 1 · 2016-08-09T19:33:24

$y = \frac{3}{8}$ $y = 3/8$

Re-arrange the terms to have all the y terms on the left and the numbers on the right.
Sometimes things can be kept really simple..

$y + \frac{1}{2} = 1 - \frac{y}{3}$ $y+ 1/2 = 1-y/3$

$y + \frac{y}{3} = 1 - \frac{1}{2} ( y + one third of y = 4/3 y)$ $y +y/3 = 1-1/2" ( y + one third of y = 4/3 y)"$

$\frac{4}{3} y = \frac{1}{2}$ $4/3 y = 1/2$

$\frac{3}{4} \times \frac{4}{3} y = \frac{1}{2} \times \frac{3}{4}$ $3/4 xx 4/3 y = 1/2 xx3/4$

$y = \frac{3}{8}$ $y = 3/8$

How do you solve y+12=1−y3 y+1/2 = 1-y/3?