How do you solve for t in $2/7(t+2/3)=1/5(t-2/3)$ ?

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Answer 1 · 2014-09-28T13:42:41

We can solve the question using the distributive property.

$2/7 ( t+ 2/3) = 1/5 (t-2/3)$

Multiplying , we get

$(2/7) * t + (2/7)*(2/3) = (1/5 ) * t - (1/5) * (2/3)$

$(2t) /7 + 4/21 = t/5 - 2/15$

Taking the like terms to one side of the equation;

$(2t)/7 -t/5 = -2/15 -4/21$

Taking LCM,

$(10t - 7t ) / 35 = ((-2 * 7 ) + (-4 * 5)) / 105$

$(3t) / 35 = -34 /105$

$3t = (-34*35 ) / 105$

$3t = (-34 * 1 ) / 3$

$3t = -34 / 3$

$t = -34 /9 = -3.7 7 or -4$

How do you solve for t in 2/7(t+2/3)=1/5(t-2/3)2/7(t+2/3)=1/5(t-2/3)?