How do you simplify first and then solve $- (1 + 7 x) - 6 (- 7 - x) = 36$ $−(1 + 7x) − 6(−7 − x) = 36$ ?

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Answer 1 · 2014-09-28T18:00:01

$- (1 + 7 x) - 6 (- 7 - x) = 36$ $-( 1 + 7x) -6 (-7-x) = 36$

it can be written as ;

$- 1 (1 + 7 x) - 6 (7 - x) = 36$ $-1 ( 1 + 7x) -6 ( 7-x) =36$

$- 1 \cdot 1 + (- 1) 7 x - 6 \cdot 7 - 6 \cdot (- x) = 36$ $-1*1 + (-1) 7x -6*7 -6*(-x)= 36$

$- 1 + - 7 x - 42 + 6 x = 36$ $-1 + -7x -42 + 6x =36$

$- 1 - 42 - 7 x + 6 x = 36$ $-1 -42 -7x +6x = 36$

$- 43 - x = 36$ $-43-x = 36$

adding $43$ $43$ to both sides

$- 43 + 43 - x = 36 + 43$ $-43 + 43 -x = 36 +43$

$- x = 79$ $-x = 79$

dividing both sides by -1 to get the value of $x$ $x$ ;

$\frac{- x}{- 1} = \frac{79}{- 1}$ $(-x) /-1 = 79 /-1$

x = -79

How do you simplify first and then solve −(1 + 7x) − 6(−7 − x) = 36−(1+7x)−6(−7−x)=36−(1 + 7x) − 6(−7 − x) = 36?