How do you solve for x in $3(x-1) = 2 (x+3)$ ?

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Answer 1 · 2014-09-28T17:53:35

3 (x-1) = 2 (x + 3)

3.x + 3 (-1) = 2.x + 2.3

$3x + (-3) = 2x +6$

$3x -3 = 2x +6$

for combining like terms either you can subtract $2x$ from the Left Hand Side ( LHS) or subtract $3x$ from the Right Hand Side ( RHS).

$3x -3 -3x = 2x + 6 -3x$

$-3 = -x + 6$

subtracting $6$ from both sides;

$-3 -6 = -x +6 -6$

$-9 = -x$

$x = 9$

How do you solve for x in 3(x-1) = 2 (x+3)3(x-1) = 2 (x+3)?