Is there a way to solve for x without using distribution in $4(x-1) = 2 (x+3)$ ?

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Answer 1 · 2014-11-07T14:50:26

Yes, there is. It might not be easier than with distribution, I will give it a shot.

$4(x-1)=2(x+3)$

by dividing by 2,

$=> 2(x-1)=x+3$

by rewriting $x+3$ as $(x-1)+4$ ,

$=> 2(x-1)=(x-1)+4$

by subtracting $(x-1)$

$=> x-1=4$

by adding 1

$=> x=5$

I hope that this was helpful.

Is there a way to solve for x without using distribution in 4(x-1) = 2 (x+3)4(x-1) = 2 (x+3)?